Question

acceleration of a particle varies with time as a equal to 12 square metre per second square. if the particle starts its motion from rest then its displacement in initial 2 second will be​

Answer 1

Answer:

ANSWER

y=mx+c

a=mt+c

For t=1   0=m+c

For t=0 −2=0+c

c=−2

a=2t−2

dtdv=2t−2

dv=(2t−2)dt

v∣0v=t2−2t∣0t=t2−2t−(0)2+2(0)=t2−2t