Physics, asked by samridhidoda, 9 months ago

Acceleration of the system is :- (all surfaces are smooth)

(1)gsin theta/2
(2)gsin theta/4
(3)gsin theta/3
(4) 3g sin theta

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Answered by nirman95

Acceleration of the whole system.

For the mass m on inclined plane:

$mg \sin( \theta) - T = ma\:\:\:\:.....(1)$

For the left mass m on the floor :

$T2 - T1 = ma\:\:\:\:.....(2)$

For the right mass m on the floor:

$T1 = ma\:\:\:\:.....(3)$

Adding all the three Equations;

$mg \sin( \theta) = 3ma$

$= > g \sin( \theta) = 3a$

$= > a = \dfrac{g \sin( \theta) }{3}$

So, final answer is:

$\boxed{ \rm{ \red{ \large{ a = \dfrac{g \sin( \theta) }{3} }}}}$

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