acceleration ue to gravity at surface of earth is'g' what will be its value inside a mine of depth R/100 of radius of earth?
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Answer:
Acceleration due to gravity changes with the height from Earth's surface as:
g
′
=g(1−
R
2h
)
⇒g
′
=9.8(1−
6400
2×100
)
⇒g
′
=9.8(1−
32
1
)=9.49m/s
2
Explanation:
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