Question

accell
Ans. (i) 12 kg-wt, (ii) 8 kg-wt, (int) 10 kg-wt.
he lift is broken, then?
Ans. 90 kg-wt, 60 kg-wt, zero.
speed of 400 ms
fires 30 bullets, ea
15. A lift is going upwards with an acceleration of 4.9 ms. What will be the apparent weight of a
60 kg man in the lift? What when the lift rises up with a uniform velocity of 4.9 ms? If the rope​

Answer 1

Answer:

Answer:-

\green{\bigstar}★ Force applied on the object is 48 N

\green{\bigstar}★ Acceleration produced = 2 m/s²

• Given :-

Mass of the object = 16 kg

Acceleration = 3 m/s²

• To Find :-

Value of the applied force = ?

Acceleration when the same force is applied on object of mass 24 kg = ?

• Solution:-

We know,

\pink{\bigstar}★ \boxed{\sf{Force [F] = mass [m] \times acceleration [a]}}

Force[F]=mass[m]×acceleration[a]

here,

Mass of the object [m] = 16 kg

Acceleration [a] = 3 m/s²

\boxed{\sf{ F = ma}}

F=ma

→ F = 16 kg x 3 m/s²

→ Force = 48 kg*m/s²

We know,

→ 1 kg*m/s² = 1 N

Therefore,

→ Force [F] = 48 N

Hence,

• Force applied on the object is 48 N

Also

When,

Mass of the object = 24 kg

Force applied = 48 N

Using the formula:-

\pink{\bigstar}★ \sf{ Acceleration [a] = \dfrac{ Force [F] }{ Mass [m]}}Acceleration[a]=

Mass[m]

Force[F]

→ Acceleration [a] = \dfrac{48}{24}

24

48

→ Acceleration [a] = 2 m/s²

Therefore,

• Acceleration produced = 2 m/s²