Question

Accept a three digit number such that the difference between the first and last digit is 2.If not then print a message "Wrong Input" .​

Answer 1

a=int(input('enter any three digit no. '))

b=int(a/100)%10 # First digit

print(b)

c=a%10 # Last digit

print(c)

if (c-b) == 2:

print('correct input')

else:

print('wrong input')

Dry run

enter any three digit no. 456

4

6

correct input

explanation

'a' will take input (like 456)

in 'b' 456/100 = 4.56 then int(4.56) = 4 then 4%10 = 4

in 'c' 456%10 = 6

c-b = 2

if (c-b) == 2 #true

correct input