Question

accept ten numbers and print only odd numbers​

Answer 1

// C++ program to print all Even  

// and Odd numbers from 1 to N  

#include <bits/stdc++.h>  

using namespace std;  

// Function to print even numbers  

void printEvenNumbers(int N)  

{  

cout << "Even: ";  

for (int i = 1; i <= 2 * N; i++) {  

 // Numbers that are divisible by 2  

 if (i % 2 == 0)  

  cout << i << " ";  

}  

}  

// Function to print odd numbers  

void printOddNumbers(int N)  

{  

cout << "\nOdd: ";  

for (int i = 1; i <= 2 * N; i++) {  

 // Numbers that are not divisible by 2  

 if (i % 2 != 0)  

  cout << i << " ";  

}  

}  

// Driver code  

int main()  

{  

int N = 5;  

printEvenNumbers(N);  

printOddNumbers(N);  

return 0;  

}  

Answer 2

Following are the program in python for the above question :

Explanation:

number=[]#take the list to store the number.

for x in range(10):#for loop which takes the 10 value as input.

   value=int(input("Enter the "+str(x+1)+" number: "))#take the input from the user.

   number.append(value)#adds the value on the list.

print("The odd number are : ",end=" ")#print the message.

for x in number:#loop to check the odd number.

   if(x%2!=0):#check the condition for the odd number.

     print(x,end=" ")#print the odd number.

Output:

• If the user inputs from 1 to 10, the the output as "The odd number are :  1 3 5 7 9".

Code Explantion :

• The above code is in python language which prints the odd number.
• There is a list that takes the number from the user and stored on the list.
• Then the for loop scans the element of the list and check the odd number.
• Then the odd number is printed on the screen.

Learn More:

• Python :brainly.in/question/14689905