Accleration due to gravity at surface of a planet is equal to that at surface of earth and density is 1.5 times that of earth. If radius of earth Is R radius of planet is.
Answers
Answered by
4
g=GMe/Re= 4/3DRe
and for planet g is equal to the earth' g
so
g for planet = g for earth
4/3pieDpRp=4/3pieDeRe (Dp=3/2De)
so the value of
Rp= 2/3Re
and for planet g is equal to the earth' g
so
g for planet = g for earth
4/3pieDpRp=4/3pieDeRe (Dp=3/2De)
so the value of
Rp= 2/3Re
Similar questions