Accomplish the following conversions: Benzoic acid to aniline
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The benzoic acid which is Benzene ring along with COOH will run in the presence of SOCl2 giving Benzoyl Chloride Benzene ring with COCl2.
Then it will react with NH3 to give Benzamide.
Then the Hoffmann Bromamide degradation reaction which will be Br2/NaOH which will show the NH2 Benzene ring that will be aniline.
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