Math, asked by donewiththis, 6 months ago

According to a recent national poll, 22% of US adults get
an average of 7 or more hours of sleep per night. Assume
this is the parameter value for the population. Suppose
you select a random sample of 50 US adults and find that
10 of them get an average of 7 or more hours of sleep per
night. Let p-hat = the proportion in the sample who get an
average of 7 or more hours of sleep per night.
The probability that 20% or less of US adults get an
average of 7 or more hours of sleep per night is 0.3664.

Does this result provide convincing evidence against the polls claim?

O No, the difference between the sample result and what we expected is not extreme enough. The probability of it occurring by chance alone is not unlikely (0.3664>0.05).

O No, there is a small chance of seeing the sample result. It is unlikely to occur by chance alone.

O Yes, the difference between the sample result and the parameter (2%) is less than 5%.

O Yes, the probability of seeing the sample result is so far from what we expected that the probability of it occurring by chance alone is very unlikely.​

Answers

Answered by yugi751
0

Answer:

No, the difference between the sample result and what we expected is not extreme enough. The probability of it occurring by chance alone is not unlikely (0.3664 > 0.05).

Step-by-step explanation:

A on edgenuity

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