Science, asked by vijaychand1482, 11 months ago

According to Bohr's principle, the relation between principal quantum number (n) and radius of orbit (r) is

Answers

Answered by Arslankincsem
1

Let us consider the Bohr model in which i rotates around the nuclei (truly charges) in a fixed stationary state and in circular orbit.

Therefore, clearly the electrostatic force is at the centripetal force.  

Mv2/r = kze2/r after equating, it comes out as v = kze2/mvr.

According to Bohr’s theories, the angular momentum L= nh/2 π, then v= kze2*2π / nh (Take this as B)

Therefore, in the equation, mv2/r = kze2/ r that gives r = kze2/mv2. Substituting the value of v from B, we get r α n2


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