Question

According to bohr's theory angular momentum of an electron in 6th orbit is

Answer 1

The angular momentum (mvr) of electron in nth orbit is equal to nh/2π. Note: nh/2π gives angular momentum of electron revolving in a circular orbit as proposed by Neils Bohr. However orbital angular momentum of electron in a given orbital is calculated by using the following equation

Answer 2

Angular momentum =
$\frac{nh}{2\pi}$
n = no. of orbit
h = plank's constant

Using the formula we get
Angular momentum =
$\frac{3h}{\pi}$