according to bohr's theory , e- of h-atom has energy , En=-13.59/n^2 eV. then determine the amount of energy required to take out an electron of He+ ion from its third orbit. what is the answer?
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Answer:En =-13.6 × Z^2/n^2
Answer:En =-13.6 × Z^2/n^2 = -13.6 × 2^2/3^2
Answer:En =-13.6 × Z^2/n^2 = -13.6 × 2^2/3^2 = -13.6 ×4/9
Answer:En =-13.6 × Z^2/n^2 = -13.6 × 2^2/3^2 = -13.6 ×4/9 = -1.51 × 4
Answer:En =-13.6 × Z^2/n^2 = -13.6 × 2^2/3^2 = -13.6 ×4/9 = -1.51 × 4 = -6.04
Answer:En =-13.6 × Z^2/n^2 = -13.6 × 2^2/3^2 = -13.6 ×4/9 = -1.51 × 4 = -6.04please mark my answer as brainliest if the answer is correct
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