Question

according to Bohr's theory if the energy of the electron of the hydrogen atom in the first orbit is -2.17×10^-18 j ' what will be the energy of the electron in the third orbit.​

Answer 1

Answer:

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Answer 2

Energy in nth orbit= $-2.17 *10^{-18} * 1/n^{2}$

Energy in 3rd orbit = $-2. 17 * 10 ^{-18}*1/9$

=$-0.241 *10^{-18}$

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