Question

according to bohr's theory the angular momentum of an electron in 5th orbital is

Answer 1

The angular momentum (mvr) of electron in nth orbit is equal to nh2πnh2π

For the electron in 5th orbit

angular momentum =mvr =5h2π5h2π

=2.5hπ

Answer 2

Answer: $2.5\ h/\pi$

Explanation:

We know that according to Bohr's theory , the angular momentum in nth orbit is given by :-

$M_0=n\dfrac{h}{2\pi}$

Given : n= 5

Then, the angular momentum of an electron in 5th orbital will be :-

$M_0=(5)\dfrac{h}{2\pi}=2.5\dfrac{h}{\pi}$

Hence, the angular momentum of an electron in 5th orbital= $2.5\ h/\pi$