Chemistry, asked by pronitanath5, 11 months ago

according to Bohr theory the radius (r) and velocity (V) of an electron vary with the increasing principle quantum number n as

Answers

Answered by aryapatil84
36

Answer:bhor radius=0.529(n²/z)A°

Velocity=2.18*10^6 (z/n)

Hence radius is directly proportional to n²(n=principal quantum no)

And velocity is inversely proportional n

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pronitanath5: what is the correct option r increases v decreases, r and v both increases, r and v both decreases, r decreases v increases
Answered by krishna210398
0

Answer:

radius is immediately proportional to n²(n=main quantum no) And speed is inversely proportional n

Explanation:

In atomic physics, the Bohr version or Rutherford–Bohr version, offered via way of means of Niels Bohr and Ernest Rutherford in 1913, is a machine such as a small, dense nucleus surrounded via way of means of orbiting electrons—much like the shape of the Solar System, however with appeal supplied via way of means of electrostatic forces in vicinity of gravity.

The radius of an orbit of revolution of electron is:  r= πme 2n 2 h 2 ϵ 0

​The speed of revolving electron is:  v= 2nhϵ 0e 2

​Hence, r∝n 2 and v∝ n1

​Therefore, lowering main quantum variety n,r will lower and v will increase.

Electron angular momentum approximately the nucleus is an integer a couple of of  2πh

​ wherein h is Planck's constant.

Thus, Iω=mvr= 2πnh

​Hence r∝n.

bohr radius=0.529(n²/z)A°

Velocity=2.18*10^6 (z/n)

Hence radius is immediately proportional to n²(n=main quantum no) And speed is inversely proportional n.

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