according to bohrs theory, the time-averaged magnetic field at the centre (i.E. Nucleus) of a hydrogen atom due to the motion of electrons in the nth orbit is proportional to. (n=principal quantum number)
Answers
Answered by
7
Hello dear,
● Answer-
B ∝ n^-5
● Explaination-
# Formulae-
r = (εn^2h^2) / (πmZe^2)
v = (Ze^2) / (2εhn)
# Solution-
Magnetic field due to flowing current-
B = μI / 2r
B = μ (ev/2πr) / 2r
B = μev / 4πr^2
B = μe[(Ze^2)/(2εhn)] / 4π[(εn^2h^2)/(πmZe^2)]^2
B = μπeZm^2 / 8ε^3h^5n^5
Therefore,
B ∝ 1/n^5
B ∝ n^-5
Hope this is useful...
● Answer-
B ∝ n^-5
● Explaination-
# Formulae-
r = (εn^2h^2) / (πmZe^2)
v = (Ze^2) / (2εhn)
# Solution-
Magnetic field due to flowing current-
B = μI / 2r
B = μ (ev/2πr) / 2r
B = μev / 4πr^2
B = μe[(Ze^2)/(2εhn)] / 4π[(εn^2h^2)/(πmZe^2)]^2
B = μπeZm^2 / 8ε^3h^5n^5
Therefore,
B ∝ 1/n^5
B ∝ n^-5
Hope this is useful...
Answered by
1
Answer:
n to the power -5
Explanation:
using bohr energy formula.
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