Question

According to complex number please simplify under root minus 2 x under root minus 3

Answer 1

Answer:

$\sqrt{ - 2} x \sqrt{ - 3} \\ = \sqrt{ - 1 \times 2}x \times \sqrt{ - 1 \times 3} \\ = \sqrt{ - 1} \times \sqrt{2} x \times \sqrt{ - 1} \times \sqrt{3} \\ = i \times \sqrt{2} x\times i \sqrt{3} \\ = {i}^{2} \times \sqrt{2 \times 3} x = - 1 \times \sqrt{6} x \\ = - \sqrt{6} x \\ since \: i = \sqrt{ - 1} \: \: and \: {i}^{2} = - 1$