Question

According to de broglie the de broglie wavelength for electron

Answer 1

According to de Broglie's wave-particle duality, the relation between electron's wavelength and momentum is λ = h / m v . ... Since de Broglie believes particles and wavehave the same traits, the two energies would be the same: m c 2 = h ν .

Answer 2

★☆〖Qบęຮτ ı¨ ø nˇ〗☆★

⭐The Dual Nature of Matter⭐

=> de-Broglie's Principle states that "All material particles in motion possess wave characteristics..."

=> de-Broglie's Relationship can be derived by combining the mass and energy relationships proposed by Max Planck, and Albert Einstein...

E = ∫c²dm = Σc²Δm = mc²

E = hν

=> The combination of these two yielded the desired result:

λ = h/mc

=> The above equation is valid for a Photon(γ⁰)

=> The same relation can be extended to every particle of this universe, if the speed of light in vacua(c) is replaced by the ordinary velocity of the particle:

$\: \: \: \: \: \: \: \: \: λ = \frac{h}{ \: mv⃗}$

____________________________________

________________

<Judge It Yourself...>

(100% Plagiarism-Free ☺️☺️)

Hope it helps you! ヅ

✪ Be Brainly ✪