according to formula of potential, electric potential is inversely proportional to charge, but, more charge means more potential, how can that be explained?
Answers
Answer:
These two equations describe completely different things.
V=W/Q says that if you have a test charge Q, and you want to move it from place-1 to place-2, and it takes an amount of work W to do it, then the potential (voltage) at place-2 is higher than that at place-1 by an amount V. The equation may make it may look like V depends on Q, but it does not: if you double the charge, it takes twice as much work to move it, and the V remains the same. The potential is a function of the pre-existing electric field, and the equation simply tells you how much work it takes to move a given amount of charge around in that field.
Q=CV says that the potential difference across a capacitor is proportional to the amount of charge on each plate of the capacitor, and defines the capacitance, C as the constant of proportionality. It is much less general than the first equation: there are many situations where the concept of capacitance is not applicable. Moreover, the charge referred to in the equation is the charge that produces the field, not one that experiences it.
Answer:
According to formula, potential is directly proportional to charge. Recall V=kQ/r.
If you are confused about V=W/Q, I will explain. Here the work is not actually a constant. Different amounts of work are done for different charges. To consider V and Q as inversely proportional, work must be same no matter whatever the charge is taken. Hope this clears your doubt.