Question

according to hardy weinberg theorem, what will be the frequency of heterozygote when r is 0.2?​

Answer 1

Answer:

The frequency of heterozygous individuals. Answer: The frequency of heterozygous individuals is equal to 2pq. In this case, 2pq equals 0.32, which means that the frequency of individuals heterozygous for this gene is equal to 32% (i.e. 2 (0.8)(0.2) = 0.32).

Explanation:

Answer 2

Explanation:

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