Question

According to Joule's law of heating, heat produced
2 H  I
Rt, where I is current, R is resistance
and t is time. If the errors in the measurement of I, R and t are 3%, 4% and 6% respectively
then error in the measurement of H is

Answer 1

Heat produced H=i2RT

Heat produced H=i2RTlogH=2logi+logR+logT

Heat produced H=i2RTlogH=2logi+logR+logTHΔH=i2Δi+RΔR+RΔT

Heat produced H=i2RTlogH=2logi+logR+logTHΔH=i2Δi+RΔR+RΔT⇒ Error in H=2×3+4+6=16%.

10 answer like for cht

Answer 2

Answer:

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