Question

According to Kepler’s third law T2rn, where n . (A) 2 (B) 3 (C) 4 (D) 1/3​

Answer 1

Answer:

according to Kepler's third law

square of time period is proportional to cube of semi major axis.

T2 proportional to r3(also applicable for electrons motion in orbits)

answer - (B)

Answer 2

According to Kepler's third law  $T^{2}$ ∝ $r^{n}$, where $n=$ (B) 3.

Explanation:

• Kepler's third law states that the square of the period of revolution $(T)$  of a planet around the sun is proportional to the third power of the average distance $r$ between sun and planet.

• $T^{2}$ ∝ $r^{3}$    

i.e  $T^{2}=Kr^{3}$  here $K$ is constant.

After applying Newton's Laws of Motion and Newton's Law of Gravity, we find that Kepler's Third Law takes a more general form:

⇒ $T^{2} =\frac{4\pi ^{2} }{G(M_{1}+M_{2}) } r^{3}$

• Where $M_{1}$ and $M_{2}$ are the masses of the two orbiting objects in solar masses.

• Note that if the mass of one body, such as $M_{1}$, is much larger than the other, then $M_{1}+M_{2}$ is nearly equal to

• In our solar system, $M_{1}=1$ solar mass and this equation become identical to the first.