According to Lagrange's mean value theorem, /(x) is continuous in [a, b],
differentiable in (a, b), then there exits ce(a, b) such that
PRN: 72142526H, NOTE: SCREENSHOT PROHIBITED
f(b-(a)
S'(c)=
ba
О А
ОВ
| (c)-S(b)-f(a)
b-a
С
S'(b)-S'(a)
S "(c)=
b-a
f'(c)=0
D
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