Question

According to Maxwell's theory of electrodynamics, an electron going in a circle should emit radiation of frequency equal to its frequency of revolution. What should be the wavelength of the radiation emitted by a hydrogen atom in ground state if this rule is followed?

Answer 1

Answer:

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Answer 2

Wavelength of Hydrogen is 45.686 nm

Explanation:

• Frequency of radiation emitted by hydrogen atom in ground state is $f = \frac {c}{\lambda}$ where c is speed and $\lambda$ denotes the wavelength.

• Now, if Maxwell’s theory of electrodynamics is true then this frequency is equal to the frequency due to revolution in the ground state by hydrogen atom which is given as-

$f = \frac {V}{2\pi r}$where v represents the velocity in ground state and r denotes radius in ground state of hydrogen atom.

Equating both the equations,

$\frac {c}{\lambda} = \frac {V}{2\pir}$

or $\lambda = \frac {2c\pi r}{V}$

or $\lambda = \frac {2 \times 3 \times 10^8 \times 3.14 \times 0.53 \times 10^{-10}}{2187 \times 10^3}$ m

= 45.686 nm