Question

according to newton's universal law of gravitation F=G m1m2÷r2.Find the dimension of G. ​

Answer 1

Answer:

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Answer 2

Explanation:

From Newton’s law of gravitation,

Force (F) = [GmM] × r-2

Gravitational Constant (G) = F × r2 × [Mm]-1 . . . . (1)

Since, Force (F) = Mass × Acceleration = M × [LT-2]

∴ The dimensional formula of force = M1 L1 T-2 . . . . (2)

On substituting equation (2) in equation (1) we get,

Gravitational Constant (G) = F × r2 × [Mm]-1

Or, G = [M1 L1 T-2] × [L]2 × [M]-2 = [M-1 L3 T-2].

Therefore, the gravitational constant is dimensionally represented as M-1 L3 T-2.

⇒ Check Other Dimensional Formulas:

Dimensions of Gravitational Potential Energy

Dimensions of Temperature

Dimensions of Linear Momentum

Dimensions of Boltzmann Constant

Dimensions of Permittivity