Physics, asked by sugamarora3757, 10 months ago

According to one of the Kepler's laws of planetary motion (a) r2 ∝ T3
(b) r ∝ T2
(c) r3 ∝ T2
(d) r3 ∝1T2

Answers

Answered by Anonymous
8

\huge{\star}{\underline{\boxed{\red{\mathfrak{Answer :}}}}}{\star}

(a) is correct answer

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\huge{\star}{\underline{\boxed{\red{\mathfrak{Explanation :}}}}}{\star}

Considerd a planet of mass m is orbiting around the sun of mass M in circular orbit of radius r , with constant angular velocity ω .

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Then,

\Large \implies {\sf{\frac{GMm}{r^2} \: = \: mr {\omega}^2 \: = \: mr( \frac{4 {\pi}^2}{GM})r^3}}

\Large \implies {\sf{T^2 \: = \: ( \frac{4 {\pi}^2}{GM})r^3}}

Now,

\huge{\boxed{\boxed{\sf{T^2 \: \propto \: r^3}}}}

Where,

∴ [4π²/GM = constant]

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So, The Answer is a

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Answered by ItzCuteChori
6

\huge{\boxed{\boxed{\mathfrak{\pink{Answer}}}}}

(a) r2 ∝ T3

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