Question

According to the above reaction, to the above reaction, how many grams of Na2co3 will be needed do obtain 11.2 litre co2 at stp​

Answer 1

Answer:

Na2CO3 does not decompose on heating.

Two moles of  NaHCO3 decomposes on heating to give two moles of CO2.

11.2 L of  CO2 corresponds to 0.5 moles of NaHCO3 (molecular weight is 84 g/mol) which corresponds to 42 g.

Hence, the percentage of Na2CO3 in the mixture is

100-42×100. = 58%.

100