Question

according to the consumer electronic manufacturers association 10% of all us household have fax machine and 52% of a personal computer suppose 91% of us household has fax machine have a personal computer us household is randomly selected what is the probability that household as fax machine and a personal computer​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Given according to the consumer electronic manufacturers association 10% of all us household have fax machine and 52% of a personal computer suppose 91% of us household has fax machine have a personal computer us household is randomly selected what is the probability that household has fax machine and a personal computer

• Given fax machine and personal computer  
• Probability of fax machine will be 10% = 0.10
• Probability of personal computer will be 52% = 0.52
• Now probability of US household having both personal computer and fax machine is 91% = 0.91
• So we have Probability of personal computer and fax machine / probability of fax machine = 0.91
•                                               So P (PC and fax mac) / p(fax mac) = 0.91
•                                               Or P(PC and fax mac) / 0.10 = 0.91
•                                               Or P(PC and fax mac) = 0.91 x 0.10
•                                                                                     = 0.091

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