Question

According to the emission spectrum of hydrogen, mercury, and neon, shown below, which colored line, in which atom represents an electron travelling the longest distance? Discuss and justify your answer.

Answer 1

Answer:

cos(90−10)sin(30)cos(90−40)cos(90−70)

=cos(80)

2

1

cos(40)cos(20)

=

4sin(20)

1

cos(80)cos(40).2sin(20)cos(20)

=

8sin(20)

1

cos(80)2.cos(40)sin(40)

=

16sin(20)

1

2cos(80)sin(80)

=

16sin(20)

1

sin(160)

=

16sin(20)

1

sin(180−20)

=

16sin(20)

1

sin(20)

=

16

1

.........R.H.S

=cos(80)2/1=cos(80) 2/1=cos(80)2/1

cos(40)cos(20)=4sin(20)1cos(40)cos(20)= 4sin(20)1cos(40)cos(20)=4sin(20)1

cos(80)cos(40).2sin(20)cos(20)=8sin(20)1cos(80)cos(40).2sin(20)cos(20)= 8sin(20)1cos(80)cos(40).2sin(20)cos(20)=8sin(20)1

cos(80)2.cos(40)sin(40)=16sin(20)1cos(80)2.cos(40)sin(40)= 16sin(20)1cos(80)2.cos(40)sin(40)=16sin(20)1

2cos(80)sin(80)=16sin(20)12cos(80)sin(80)= 16sin(20)12cos(80)sin(80)=16sin(20)1

sin(160)=16sin(20)1sin(160)= 16sin(20)1sin(160)=16sin(20)1

sin(20)=16/1sin(20)= 16/1sin(20)=16/1

.........