Question

According to the equation CaCO3+2HCl=CaCl2+CO2+H2O what mass of CaCO3 is required to react with 15.2 gram of HCl?

Answer 1

Answer:

Using morality, Number of moles are calculated for 1000ml or 1L of the solution.

1000ml contains 0.75MHCl

HCl=0.75 mole.

Therefore, 25ml of 0.75M HCl will contains HCl=

1000

0.75×25

=0.01875mole

2 moles of HCl reacts with =1mole of CaCO

3

Therefore,

0.01875 mole of HCl will react with =

2

1×0.01875

=0.009375mole

Molar mass of CaCO

3

=100g

Hence, the mass of 0.009375 of CaCO

3

=no.ofmoles×molarmass=0.9375g