According to the law of constant proportions what mass of oxygen would be present in a sample of carbon dioxide containing 3 grams of carbon
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hey mate ,
mass of carbon = 12u
mass of O2= 16*2=32u
ratio of their masses = 12/32
= 3/8
=3:8
so, when 3 g of carbon is there in co2 then 8 g of oxygen is present there
mass of carbon = 12u
mass of O2= 16*2=32u
ratio of their masses = 12/32
= 3/8
=3:8
so, when 3 g of carbon is there in co2 then 8 g of oxygen is present there
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