According to the uniform prudent investor act, a trustee's investment and management decisions should be evaluated: (a) both as part of a beneficiary's investment strategy, and as an individual transaction. (b) both as part of the trustee's overall investment strategy, and as an individual transaction. (c) both as part of the trustee's overall investment strategy, and as part of the entire portfolio. (d) both as part of the beneficiary's investment strategy and as part of the entire portfolio
Answers
2
−224x+25y
2
+250y−191=0
:⟹(4x)
2
+28
2
−224x−28
2
+(5y)
2
+25
2
+250y−25
2
−191=0
:⟹(4x−28)
2
+(5y+25)
2
=191+625+784
:⟹(4x−28)
2
+(5y+25)
2
=1600
:⟹
1600
(4x−28)
2
+
1600
(5y+25)
2
=1
:⟹
1600
16(x−7)
2
+
1600
25(y+5)
2
=1
:⟹
100
(x−7)
2
+
64
(y+5)
2
=1
:⟹
10
2
(x−7)
2
+
8
2
(y+5)
2
=1
\begin{gathered}\text{It \: is \: in \: the \: form \: of} \\ \\ \tt: \implies \frac{ {X}^{2} }{ {a}^{2} } + \frac{ {Y}^{2} }{ {b}^{2} } = 1 \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies x = 0 \\ \\ \tt: \implies x - 7 = 0 \\ \\ \tt: \implies x = 7 \\ \\ \tt: \implies Y = 0 \\ \\ \tt: \implies y + 5 = 0 \\ \\ \tt: \implies y = - 5 \\ \\ \green{\tt \therefore Center(7,- 5)} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies X = 0 \\ \\ \tt: \implies x - 7 = 0 \\ \\ \tt: \implies x = 7\end{gathered}
It is in the form of
:⟹
a
2
X
2
+
b
2
Y
2
=1
Asweknowthat
:⟹x=0
:⟹x−7=0
:⟹x=7
:⟹Y=0
:⟹y+5=0
:⟹y=−5
∴Center(7,−5)
Asweknowthat
:⟹X=0
:⟹x−7=0
:⟹x=7
\begin{gathered}\tt: \implies Y = \pm b \\ \\ \tt: \implies y + 5 = \pm 8 \\ \\ \tt: \implies y = -13 \: and \: 3 \\ \\ \green{\tt \therefore Vertex(7,-13) \: and \: (7,3)} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies {a}^{2} = {b}^{2} ( {e}^{2} - 1) \\ \\ \tt: \implies 100 = 64( {e}^{2} - 1) \\ \\ \tt: \implies \frac{100}{64} = {e}^{2} - 1 \\ \\ \tt: \implies \frac{25}{16} + 1 = {e}^{2} \\ \\ \tt: \implies e = \frac{ \sqrt{41} }{4} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies x = 7 \\ \\ \tt: \implies Y = \pm be \\ \\ \tt: \implies y + 5 = \pm 8 \times \frac{ \sqrt{41} }{4} \\ \\ \tt: \implies y + 5= \pm 2 \sqrt{41} \\ \\ \tt: \implies y = \pm 2 \sqrt{41} - 5 \\ \\ \green{\tt \therefore Foci (7,\pm 2\sqrt{41} - 5)}\end{gathered}
:⟹Y=±b
:⟹y+5=±8
:⟹y=−13and3
∴Vertex(7,−13)and(7,3)
Asweknowthat
:⟹a
2
=b
2
(e
2
−1)
:⟹100=64(e
2
−1)
:⟹
64
100
=e
2
−1
:⟹
16
25
+1=e
2
:⟹e=
4
41
Asweknowthat
:⟹x=7
:⟹Y=±be
:⟹y+5=±8×
4
41
:⟹y+5=±2
41
:⟹y=±2
41
−5
∴Foci(7,±2
41
−5)