Question

According to v-t graph given below ,distance of the object from 4 to 10 seconds. 10 m 11 m 12 m 13 m​

Answer 1

Distance travelled will be,

• Sum of areas of all the enclosed shapes.

Now, the total distance travelled;

• Note:- I'm considering the area of shapes from 4 sec - 10 sec

= Area of triangle + Area of triangle( deacclerated motion doesn't matter as we just need to find total distance) + area of sqaure

= (½ × b × h) - (½×b×h) + (a × a)

= (½ × 2 × 4) - (½ × 2 × 3 ) + (2 × 2)

= 4 + 3 + 4

= 7 + 4

= 11 m

Therefore, the total distance travelled is 11 m.

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