Question

According to VSEPR theory the shape of SF4 molecule is

Answer 1

★ Diagram:

$\setlength{\unitlength}{30}{\begin{picture}(0, 0)\put(1, 1){ \tt{S} }\put(1, 1){ : }\put(1, 1){ : }\put(1.25, 1.5){\line(0, 1){1}}}\put(1.25,-0.2){\line(0, 1){1}}\put(1.25, 2.7){ \tt{ F } }\put(1, -0.8){ \tt{ F } }\put(1.4, 1.2){\line(1, 1){1}}\put(1.4, 1){\line(1, -1){1}}\put(2.4, -0.2){ \tt{ F } }\put(2.35, 2.25){ \tt{F} }\end{picture}}$

★ More info:

About SF₄ MOLECULE

Total no. of bonds pairs : 4

Total no. of lone pairs : 1

Type of Hybridisation : sp³d

Shape of molecule : see - saw

Type of molecule : AB₄E

Here ,

• A : element with single atom : S
• B₄ : element with 4 atoms : F₄
• E : no. of lone pairs : 1 lone pair

About sp³d Hybridisation

This type of Hybridisation involves the mixing of one s , three p and one d orbital resulting in the formation of five equivalent sp³d hybrid orbitals

Examples : PF₅ , PCl₅ , XeO₂F₂ , XeF₂

About sp³d² Hybridisation

This type of Hybridisation involves the intermixing of one s , three p & two d orbitals resulting in the formation of six equivalent sp³d² hybrid orbitals

Examples : BrF₅ SF₆ , XeO₂F₄