Question

Account for the following:
(i) $N_{2}$ has a higher bond dissociation energy than NO.
(ii) $N_{2}$ and CO both have the same bond order but CO is more reactive than $N_{2}$.

Answer 1

(i) $N_{ 2 }$ molecule has 14 electrons totally. Three is the bond order in  $N_{ 2 }$ . In NO molecule ,2.5 is the bond order. So, the order of bond for  $N_{ 2 }$  molecule is greater than NO molecule. Hence  $N_{ 2 }$ molecule has higher bond dissociation energy than NO.

(ii) “Three is the order of bond for CO” .  $N_{ 2 }$ molecule which is equal to CO. Both  $N_{ 2 }$  and CO are isoelectronic. Because of high electronegativity difference, CO is highly reactive than  $N_{ 2 }$ . And CO is also more polar than  $N_{ 2 }$.