Computer Science, asked by AjPicks2004, 20 days ago

accumulator of 8085 contains data F9h and register C contains 48h. what will be contents of accumulator after exceution of SUBC* ​

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Answers

Answered by sghvsanthosh8a
0

Answer:

E: ADD E with Accumulator

Before execution : [A] = 71H

instruction: ADD E

71 H = 01110001

ADD 39 H = 00111001

10101010 = AA H

After execution [A] = AA H

[Cy] = 00H

(ii) ORA E Logically OR with Acc Before execution : [A] = 71H

Instruction: ORA E

71 H 01110001

ORA 39 H 00111001

011110 01 = 79 H

After execution : [A] = 79H

RRC: Rotate accumulator right by one

bit.

Before execution : [A] = 71H01 1100

01Instruction: RRC

After execution [A] = 1 0 1 1 1 0 0 0 = B8

H

[A] = B8H [Cy] = 01H

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