Question

∠ACD is an exterior angle of ∆ABC, if ∠A = 50°, ∠B = 75°, then ∠ACD = ----------​

Answer 1

Answer:

Angle ACD will be 125degree.

Step-by-step explanation:

According to exterior angle property,

The sum of the two angles of a triangle is equal to it's opposite interior angle.

Therefore, Angle A + Angle B = Angle ACD

50degree + 75degree = 125degree

Angle ACD = 125degree

Answer 2

Solution :-

Given ,

• ∠ACD is an exterior angle
• ∠A = 50°
• ∠B = 75°

We need to find ,

• ∠ACD = ?

By observing the given figure in the attachment

Now finding ∠ACD using exterior angle property of triangle .

• Exterior angle property :- Exterior angle of triangle is equal to sum of two interior opposite angles of the triangle .

♦ In other form ( from this question ) :-

→ ∠ACD = ∠A + ∠B

Now substituting the values of angles A & B

→ ∠ACD = 50° + 75°

→ ∠ACD = 125°

Hence , ∠ACD = 125°