Question

ACD is an exterior angle of ABC. If AC = BC and ABC = 45°, then find ACD.​

Answer 1

Answer:

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

Hence, In this case ∠A and ∠B

So,

∠A+∠B=140

∘

as ∠A=∠B

or,2∠A=140

∘

∠A=∠B=70

∘

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Answer 2

Answer:

angle acd = 90degree

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