∠ACD is an exterior angle of ∆ABC. m∠A = 70° and m∠ACD = 120°. Find m ∠B and m ∠ACB.
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Answer:
angle B= 50 degrees. angle ACB = 60 degrees
Step-by-step explanation:
by exterior angle property,
angle A + angle B = angle ACD
70+ angle B= 120
angle B= 50 degrees
By angle sum property of a triangle,
angle A + angle B + angle ACB = 180 degrees
70+50+angle ACB=180
angle ACB= 60 degrees
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