Math, asked by deekshitha5384, 8 months ago

∠ACD is an exterior angle of ∆ABC. m∠A = 70° and m∠ACD = 120°. Find m ∠B and m ∠ACB.

Answers

Answered by anuneet16
5

Answer:

angle B= 50 degrees. angle ACB = 60 degrees

Step-by-step explanation:

by exterior angle property,

angle A + angle B = angle ACD

70+ angle B= 120

angle B= 50 degrees

By angle sum property of a triangle,

angle A + angle B + angle ACB = 180 degrees

70+50+angle ACB=180

angle ACB= 60 degrees

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