Acetaldehyde reacts with semicarbazide and
forms semicarbazone. Its structure is
(a) CH₃CH = NNHCON = CHCH₃ (b) CH₃CH = NNHCONH₂
(c) CH₃CH = N— N — CONH
|
OH
(d) CH₃CH = N—CONHNH₂
nazeerahamed1974cta:
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Explanation:
Acetaldehyd
forms semicarbazone. Its structure is
(a) CH₃CH = NNHCON = CHCH₃ (b) CH₃CH = NNHCONH₂
Which is the perfect answer a r b??
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