acetamides reacts with bromine and KOH to give
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Methanamine will be the product... It's Hoffman bromide degradation rxn
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Heyyaa,
● Hoffman degradation reaction -
- Primary amide reacts with Br2 in presence of KOH to produce primary amine with one C-atom less.
R-CONH2 + Br2 + 4KOH ---> R-NH2 + 2KBr + K2CO3 + 2H2O
- This is rearrangement type of reaction.
- Acetamide reacts with bromine in presence of potassium hydroxide to to give methylamine.
CH3CONH2 + Br2 + 4KOH --> CH3NH2 + K2CO3 + 2KBr + 2H2O
Hope this helps...
● Hoffman degradation reaction -
- Primary amide reacts with Br2 in presence of KOH to produce primary amine with one C-atom less.
R-CONH2 + Br2 + 4KOH ---> R-NH2 + 2KBr + K2CO3 + 2H2O
- This is rearrangement type of reaction.
- Acetamide reacts with bromine in presence of potassium hydroxide to to give methylamine.
CH3CONH2 + Br2 + 4KOH --> CH3NH2 + K2CO3 + 2KBr + 2H2O
Hope this helps...
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