Question

Acetyl bromide reacts with excess of CH₃MgI followed by treatment with a saturated solution of NH₄Cl gives
(a) 2-methyl-2-propanol
(b) acetamide
(c) acetone
(d) acetyl iodide

Answer 1

hi dear....

correct option is a) 2-methyl-2-propanol

explanation :- reffered to the attached file.....

hope I answered your question.....

Answer 2

$\huge\bold\pink{hello!!}$

HERE IS UR ANSWER

____________________❤

option A is correct