Acetylene C2H2 burns in air forming carbon dioxide CO2 and water vapour H2O .Calculate the volume of air required to completely burn 50 cm cube of acetylene. Assume air contains 20% oxygen...
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C2H2 is acetylene
C2H2+3O2----> 2Co2+H20
volume of O2 required to burn 1 ml of acetylene equal to 3 ml then volume of water required to burn 50 ml of acetylene equal to 150 ml of oxygen...
as 20 ml of O2 is present in 100 ml of gas mixture.
then 150 ml of 02 is present in 100×150/20 = 750 ml of gaseous mixture
C2H2+3O2----> 2Co2+H20
volume of O2 required to burn 1 ml of acetylene equal to 3 ml then volume of water required to burn 50 ml of acetylene equal to 150 ml of oxygen...
as 20 ml of O2 is present in 100 ml of gas mixture.
then 150 ml of 02 is present in 100×150/20 = 750 ml of gaseous mixture
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