Acetylene is treated with excess sodium in liquid ammonia. The product is reacted with excess methyl iodide. The final product is ............... .
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Acetylene is treated with excess sodium in liquid ammonia. The product is reacted with excess methyl iodide. The final product is
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Answer: butyne is the correct answer.
Explanation:
The reaction goes as follows:
Acetylene is treated with excess sodium in liquid ammonia. The product is reacted with excess methyl iodide.
Acetylene has formula C2H2.
The IUPAC name of acetylene is ethyne.
It is known as the simplest form of compund.
It is very reactive.
It's reactive and hence it reacts with Na. Acetylene contains 2 hydrogen atoms.
When it is reacted with excess Na, disodoum Acetylde is formed.
The product disodoum Acetylde when reacts with methyl chloride, 2 butyne is obtained.
Disodoum Acetylde ha formula C2HNa.
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