Question

Acharya quadratic formula.Ans.
Exercise 3.4
0. 1. Solve the following equations by the
method of completing square.
(i) 3x2 – 5x + 2 = 0​

Answer 1

Step-by-step explanation:

3x² -5x +2 =0

Now divide the x² coefficient throughout,

⇒x²- 5x/3+2/3=0

Divide the coefficient of x by 2, and square it and add it and subtract it in the equation,

⇒x²-5x/3+2/3+25/36 -25/36 =0

⇒x²-5x/3+25/36 =1/36

⇒(x-5/6)²=(1/6)²

⇒x-5/6=plus or minus 1/6

x-5/6=1/6 (or) x-5/6= -1/6 ⇒x= -1/6+5/6⇒x=4/6 ⇒x=2/3.

x=1.

x=1(or)2/3.

Answer 2

Answer:

2/3  , 1

Step-by-step explanation:

3x² – 5x + 2 = 0​

5x in above equation can be written as 3x + 2x

3x² – (3x + 2x) + 2 = 0​

=> 3x² - 3x  -2x +2 =0

=> 3x(x - 1) -2(x - 1) =0

=> (3x - 2)(x - 1) = 0

=> x =2/3  or 1