Achild has a die whose six faces show the letters as given below
1| 4 5 1
2 3
The die is thrown once, What is the probability of getting () 1?
(ii) 4 ?
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Answer:
i....1/3
ii....1/6
Step-by-step explanation:
no of one in die = 2
probability = 2/6 =1/3
no of 4 in die = 1
probability = 1/6
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