Question

Achord of a circle of radius 6cm is making an angle 60° at the centre. Find the
length of the chord


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Answer 1

Answer:

IN TRIANGLE AOB, AO=BO=6cm

THEREFORE,∠OAB=∠OBA=y(say)

IN TRIANGLE AOB BY ANGLE SUM PROPERTY

60°+y+y=180°⇒180°-60°=2y⇒120°=2y⇒y=60°

THEREFORE AS ∠A=∠B=∠C=60°

THEREFORE TRIANGLE AOB IS AN EQUILATERAL TRIANGLE

⇒LENGTH OF CHORD AB =6cm.