Acidified K2Cr207 solution turns green when S02 gas is passed through it due to formation of
(a) Cr2(SO4)3
(b) CrO42-
(c) Cr2(SO3)3
(d) CrSO4
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Answer:
(a)cr2(so4)3
Explanation:
This reaction is taken as an experimental verification for the presence of sulphur dioxide gas (SO2).
The equation for the reaction may be stated as follows:-
K2Cr2O7 + H2SO4 + 3SO2 ——— K2SO4 + Cr2(SO4)3 + H2O.
The orange-coloured dichromate solution will turn green due to the formation of chromium(III) sulphate, Cr2(SO4)3.
It is a redox reaction. Here:-
The oxidising agent is potassium dichromate and the reducing agent is sulphur dioxide.
Hope it helps!!!!
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