Question

Acidified water from certain reservoir kept at a potential v

Answer 1

Answer:

(a^2/2r^2)v

Explanation:

potential of one droplet= v = kq/r

let, n = number of water droplets required to fill half of  the sphere

therefore,n(4/3$\pi$ r^3) = 1/2(4/3$\pi$ a^3)

on solving, n= a^3/2r^3

now, potential of sphere due to n droplets = n(kq/a) = a^3/2r^3(kq/a) =(a^2/2r^3) kq =(a^2/2r^2)v     [ since, v = kq/r]