Question

Acidified water is electrolysed using an inert electrode the volume of gases liberated is 0.168 lit.

Answer 1

Answer:

Acidified water was electrolysed using an inert electrode and volume of gases liberated at stp was 168 ml. The amount of electricity ... 3x = 168 ml = 0.168 l x = 0.056 l

Answer 2

Explanation:

Electrolytis of acidified water occurs as follows-

2H20 ---> 2H2 + O2

Initial m 2x x

Equilb. m-x 2x x

Hence, 2x+x = 3x liberated

3x = 168 ml = 0.168 l

x = 0.056 l

V(H2) = 0.112 l

V(O2) = 0.056 l

We know electricity passed through 11.2 l H2 is 1 F.

For 0.112 l H2,

I = 1F/100 = 0.01 F

I = 0.01 × 96500

I = 965 C

Amount of electricity paased will be 965 C.

Hope this is useful...